4^80=n

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Solution for 4^80=n equation: 



4^80=n

We move all terms to the left:

4^80-(n)=0

We add all the numbers together, and all the variables

-1n+48+1.4615016373309E=0

We add all the numbers together, and all the variables

-1n+51.97277334302=0

We move all terms containing n to the left, all other terms to the right

-n=-51.97277334302

n=-51.97277334302/-1

n=51+0.97277334302/1

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